Does this equal 5, 1 or 0.
Why?
quote:
Elvish Crack Piper thought this was the Ricky Martin Fan Club Forum and wrote:
Whats the ! mean?
5x4x3x2x1
!X = X * !(X-1)
Or...!7 = 7*6*5*4*3*2*1
5! = 5x4x3x2x1
9! = 9x8x7x6x5x4x3x2x1
etc...
5*5*5 - 5! = 5
Delidgamond fucked around with this message on 11-14-2004 at 08:11 PM.
edit: wow
Thats really easy.
quote:
Doomie had this to say about Pirotess:
1, (125 - 120)/5 = 1, so regardless of what you divide or multiply by, it'll always be 1.
Actually, it looks like it is (5*5*5-5!)/5(5*5*5-5!)
Which would reduce down to (5)/5(5)
If I remember correctly, multiplication comes before division, so you'd have (5)/25, or .20
So, I don't think it would be either 5, 1, or 0. It would never quite reach 0, but would eventually get incredibly close.
Course, there is a reason I failed Pre-Calculus, so I could be wrong.
quote:
Falaanla Marr stopped staring at Deedlit long enough to write:
Actually, it looks like it is (5*5*5-5!)/5(5*5*5-5!)Which would reduce down to (5)/5(5)
If I remember correctly, multiplication comes before division, so you'd have (5)/25, or .20
So, I don't think it would be either 5, 1, or 0. It would never quite reach 0, but would eventually get incredibly close.
Course, there is a reason I failed Pre-Calculus, so I could be wrong.
Yup.
1. Parentheses
2. Exponents
3. Multiplication
4. Division
5. Addition
6. Subtraction
quote:
Waisz had this to say about John Romero:
Guys, that's an implied exponent. And the division is going on that exponent.
Oh, I thought it did that for some other reason. Being that it is an exponent, it would be 1 and not some other number.
quote:
Falaanla Marr thought about the meaning of life:
Oh, I thought it did that for some other reason. Being that it is an exponent, it would be 1 and not some other number.
The number is 1, 5, and 0. There's no given formula, so it's entirely dependent on how many iterations there are; it can be odd or even, and it's an infinite number of iterations, so....
If this doesn't make any sense, think of it this way. (5*5*5-5!)/5 = 1 If it "ends" on an exponentless 5 in a denominator, start moving up the chain... 5^1 = 5, (5*5*5-5!)/5 = 1 again. You're going to get 5/1 as your final iteration.
On the other hand, imagine it ends on an exponent, 5^(5^3-5!) = 5^5 = 3125. Moving up, (5*5*5-5!)/3125 = 1/625. 5^(1/625) = nearly 1. 5/nearly 1 = nearly 5 (slightly less). 5^5- = 3125-, 5/3125- = slightly more than 1/625. etc etc. You're getting one number which is shifting down and one which is shifting up. This part gets really odd but I think one number will eventually get to 1 and the other to infinity; these two numbers are the denominator of 5^3-5!, so you would get 5 and 0.
So it's... yeah....
